(5/3)+3x=(4/5x)+15

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Solution for (5/3)+3x=(4/5x)+15 equation: 



(5/3)+3x=(4/5x)+15

We move all terms to the left:

(5/3)+3x-((4/5x)+15)=0



Domain of the equation: 5x)+15)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x-((+4/5x)+15)+(+5/3)=0

We get rid of parentheses

3x-((+4/5x)+15)+5/3=0

We calculate fractions


3x+()/5x+15)*3)+25x/5x+15)*3)=0

We calculate fractions


3x+(()*5x)/25x^2+15*3)+25x*5x)/25x^2=0

We multiply all the terms by the denominator


3x*25x^2+(()*5x)+15*3)+25x*5x)=0



We calculate terms in parentheses: +(()*5x), so:

()*5x



Wy multiply elements

75x^3+225x^2+(()*5x)=0



We calculate terms in parentheses: +(()*5x), so:

()*5x



We do not support expression: x^3

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