5/7(10x-7)=45

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Solution for 5/7(10x-7)=45 equation: 



5/7(10x-7)=45

We move all terms to the left:

5/7(10x-7)-(45)=0



Domain of the equation: 7(10x-7)!=0

x∈R



We multiply all the terms by the denominator


-45*7(10x-7)+5=0

Wy multiply elements

-315x(1+5=0

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