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5/6b=1(7/8)
We move all terms to the left:
5/6b-(1(7/8))=0
Domain of the equation: 6b!=0We add all the numbers together, and all the variables
b!=0/6
b!=0
b∈R
5/6b-(1(+7/8))=0
We calculate fractions
()/48b^2+(-(1(+7*6b)/48b^2=0
We multiply all the terms by the denominator
(-(1(+7*6b)+()=0
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