-4(v+2)=4v-7+2(5v+1)

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Solution for -4(v+2)=4v-7+2(5v+1) equation: 



-4(v+2)=4v-7+2(5v+1)

We move all terms to the left:

-4(v+2)-(4v-7+2(5v+1))=0

We multiply parentheses

-4v-(4v-7+2(5v+1))-8=0



We calculate terms in parentheses: -(4v-7+2(5v+1)), so:

4v-7+2(5v+1)

determiningTheFunctionDomain
4v+2(5v+1)-7

We multiply parentheses

4v+10v+2-7

We add all the numbers together, and all the variables

14v-5

Back to the equation:

-(14v-5)



We get rid of parentheses

-4v-14v+5-8=0

We add all the numbers together, and all the variables

-18v-3=0

We move all terms containing v to the left, all other terms to the right

-18v=3

v=3/-18

v=-1/6

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