2w+2-2(-4w-4)=2(w-2)

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Solution for 2w+2-2(-4w-4)=2(w-2) equation: 



2w+2-2(-4w-4)=2(w-2)

We move all terms to the left:

2w+2-2(-4w-4)-(2(w-2))=0

We multiply parentheses

2w+8w-(2(w-2))+8+2=0



We calculate terms in parentheses: -(2(w-2)), so:

2(w-2)

We multiply parentheses

2w-4

Back to the equation:

-(2w-4)



We add all the numbers together, and all the variables

10w-(2w-4)+10=0

We get rid of parentheses

10w-2w+4+10=0

We add all the numbers together, and all the variables

8w+14=0

We move all terms containing w to the left, all other terms to the right

8w=-14

w=-14/8

w=-1+3/4

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