7(r+2)=5(r+4)

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Solution for 7(r+2)=5(r+4) equation: 



7(r+2)=5(r+4)

We move all terms to the left:

7(r+2)-(5(r+4))=0

We multiply parentheses

7r-(5(r+4))+14=0



We calculate terms in parentheses: -(5(r+4)), so:

5(r+4)

We multiply parentheses

5r+20

Back to the equation:

-(5r+20)



We get rid of parentheses

7r-5r-20+14=0

We add all the numbers together, and all the variables

2r-6=0

We move all terms containing r to the left, all other terms to the right

2r=6

r=6/2

r=3

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