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5/2x+8=4x
We move all terms to the left:
5/2x+8-(4x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-4x+5/2x+8=0
We multiply all the terms by the denominator
-4x*2x+8*2x+5=0
Wy multiply elements
-8x^2+16x+5=0
a = -8; b = 16; c = +5;
Δ = b2-4ac
Δ = 162-4·(-8)·5
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{26}}{2*-8}=\frac{-16-4\sqrt{26}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{26}}{2*-8}=\frac{-16+4\sqrt{26}}{-16} $
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