6x-2(x+4)=(x+2)+x-5

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Solution for 6x-2(x+4)=(x+2)+x-5 equation: 



6x-2(x+4)=(x+2)+x-5

We move all terms to the left:

6x-2(x+4)-((x+2)+x-5)=0

We multiply parentheses

6x-2x-((x+2)+x-5)-8=0



We calculate terms in parentheses: -((x+2)+x-5), so:

(x+2)+x-5

We add all the numbers together, and all the variables

x+(x+2)-5

We get rid of parentheses

x+x+2-5

We add all the numbers together, and all the variables

2x-3

Back to the equation:

-(2x-3)



We add all the numbers together, and all the variables

4x-(2x-3)-8=0

We get rid of parentheses

4x-2x+3-8=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2

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