3(y-2)+2y=2(2y+9)-4

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Solution for 3(y-2)+2y=2(2y+9)-4 equation: 



3(y-2)+2y=2(2y+9)-4

We move all terms to the left:

3(y-2)+2y-(2(2y+9)-4)=0

We add all the numbers together, and all the variables

2y+3(y-2)-(2(2y+9)-4)=0

We multiply parentheses

2y+3y-(2(2y+9)-4)-6=0



We calculate terms in parentheses: -(2(2y+9)-4), so:

2(2y+9)-4

We multiply parentheses

4y+18-4

We add all the numbers together, and all the variables

4y+14

Back to the equation:

-(4y+14)



We add all the numbers together, and all the variables

5y-(4y+14)-6=0

We get rid of parentheses

5y-4y-14-6=0

We add all the numbers together, and all the variables

y-20=0

We move all terms containing y to the left, all other terms to the right

y=20

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