2(z+5)+5(z+2)=10(z-1)

Solution for 2(z+5)+5(z+2)=10(z-1) equation:

2(z+5)+5(z+2)=10(z-1)

We move all terms to the left:

2(z+5)+5(z+2)-(10(z-1))=0

We multiply parentheses

2z+5z-(10(z-1))+10+10=0


We calculate terms in parentheses: -(10(z-1)), so:

10(z-1)

We multiply parentheses

10z-10

Back to the equation:

-(10z-10)


We add all the numbers together, and all the variables

7z-(10z-10)+20=0

We get rid of parentheses

7z-10z+10+20=0

We add all the numbers together, and all the variables

-3z+30=0

We move all terms containing z to the left, all other terms to the right

-3z=-30

z=-30/-3

z=+10