5(2k-1)=35

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Solution for 5(2k-1)=35 equation: 



5(2k-1)=35

We move all terms to the left:

5(2k-1)-(35)=0

We multiply parentheses

10k-5-35=0

We add all the numbers together, and all the variables

10k-40=0

We move all terms containing k to the left, all other terms to the right

10k=40

k=40/10

k=4

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