2=(10+z)/(-3)

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Solution for 2=(10+z)/(-3) equation: 



2=(10+z)/(-3)

We move all terms to the left:

2-((10+z)/(-3))=0

We add all the numbers together, and all the variables

-((z+10)/(-3))+2=0

We multiply all the terms by the denominator


-((z+10)+2*(-3))=0



We calculate terms in parentheses: -((z+10)+2*(-3)), so:

(z+10)+2*(-3)

We add all the numbers together, and all the variables

(z+10)-6

We get rid of parentheses

z+10-6

We add all the numbers together, and all the variables

z+4

Back to the equation:

-(z+4)



We get rid of parentheses

-z-4=0

We add all the numbers together, and all the variables

-1z-4=0

We move all terms containing z to the left, all other terms to the right

-z=4

z=4/-1

z=-4

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