5+5=10x2=20

Solution for 5+5=10x2=20 equation:

5+5=10x^2=20

We move all terms to the left:

5+5-(10x^2)=0

We add all the numbers together, and all the variables

-10x^2+10=0

a = -10; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-10)·10
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-10}=\frac{-20}{-20}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-10}=\frac{20}{-20}
=-1
$