2(y+3)=3(2y-2)

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Solution for 2(y+3)=3(2y-2) equation: 



2(y+3)=3(2y-2)

We move all terms to the left:

2(y+3)-(3(2y-2))=0

We multiply parentheses

2y-(3(2y-2))+6=0



We calculate terms in parentheses: -(3(2y-2)), so:

3(2y-2)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We get rid of parentheses

2y-6y+6+6=0

We add all the numbers together, and all the variables

-4y+12=0

We move all terms containing y to the left, all other terms to the right

-4y=-12

y=-12/-4

y=+3

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