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7(2x-5)=2(5x+3)
We move all terms to the left:
7(2x-5)-(2(5x+3))=0
We multiply parentheses
14x-(2(5x+3))-35=0
We calculate terms in parentheses: -(2(5x+3)), so:We get rid of parentheses
2(5x+3)
We multiply parentheses
10x+6
Back to the equation:
-(10x+6)
14x-10x-6-35=0
We add all the numbers together, and all the variables
4x-41=0
We move all terms containing x to the left, all other terms to the right
4x=41
x=41/4
x=10+1/4
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