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(2x-6)x=180
We move all terms to the left:
(2x-6)x-(180)=0
We multiply parentheses
2x^2-6x-180=0
a = 2; b = -6; c = -180;
Δ = b2-4ac
Δ = -62-4·2·(-180)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{41}}{2*2}=\frac{6-6\sqrt{41}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{41}}{2*2}=\frac{6+6\sqrt{41}}{4} $
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