5(y+2)=3(y-1)

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Solution for 5(y+2)=3(y-1) equation: 



5(y+2)=3(y-1)

We move all terms to the left:

5(y+2)-(3(y-1))=0

We multiply parentheses

5y-(3(y-1))+10=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

5y-3y+3+10=0

We add all the numbers together, and all the variables

2y+13=0

We move all terms containing y to the left, all other terms to the right

2y=-13

y=-13/2

y=-6+1/2

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