3(x+2)-7x=6(x-2)+8x

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Solution for 3(x+2)-7x=6(x-2)+8x equation: 



3(x+2)-7x=6(x-2)+8x

We move all terms to the left:

3(x+2)-7x-(6(x-2)+8x)=0

We add all the numbers together, and all the variables

-7x+3(x+2)-(6(x-2)+8x)=0

We multiply parentheses

-7x+3x-(6(x-2)+8x)+6=0



We calculate terms in parentheses: -(6(x-2)+8x), so:

6(x-2)+8x

We add all the numbers together, and all the variables

8x+6(x-2)

We multiply parentheses

8x+6x-12

We add all the numbers together, and all the variables

14x-12

Back to the equation:

-(14x-12)



We add all the numbers together, and all the variables

-4x-(14x-12)+6=0

We get rid of parentheses

-4x-14x+12+6=0

We add all the numbers together, and all the variables

-18x+18=0

We move all terms containing x to the left, all other terms to the right

-18x=-18

x=-18/-18

x=1

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