5y+2=3(y-1)

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Solution for 5y+2=3(y-1) equation: 



5y+2=3(y-1)

We move all terms to the left:

5y+2-(3(y-1))=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

5y-3y+3+2=0

We add all the numbers together, and all the variables

2y+5=0

We move all terms containing y to the left, all other terms to the right

2y=-5

y=-5/2

y=-2+1/2

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