12(2x+3)+6x=8(2x+2)-7

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Solution for 12(2x+3)+6x=8(2x+2)-7 equation: 



12(2x+3)+6x=8(2x+2)-7

We move all terms to the left:

12(2x+3)+6x-(8(2x+2)-7)=0

We add all the numbers together, and all the variables

6x+12(2x+3)-(8(2x+2)-7)=0

We multiply parentheses

6x+24x-(8(2x+2)-7)+36=0



We calculate terms in parentheses: -(8(2x+2)-7), so:

8(2x+2)-7

We multiply parentheses

16x+16-7

We add all the numbers together, and all the variables

16x+9

Back to the equation:

-(16x+9)



We add all the numbers together, and all the variables

30x-(16x+9)+36=0

We get rid of parentheses

30x-16x-9+36=0

We add all the numbers together, and all the variables

14x+27=0

We move all terms containing x to the left, all other terms to the right

14x=-27

x=-27/14

x=-1+13/14

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