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5(x-2)+x=6(x+3-4x
We move all terms to the left:
5(x-2)+x-(6(x+3-4x)=0
We add all the numbers together, and all the variables
5(x-2)+x-(6(-3x+3)=0
We add all the numbers together, and all the variables
x+5(x-2)-(6(-3x+3)=0
We multiply parentheses
x+5x-(6(-3x+3)-10=0
We add all the numbers together, and all the variables
6x-(6(-3x+3)-10=0
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