(1/4)(2(x-1))+10=x

Solution for (1/4)(2(x-1))+10=x equation:

(1/4)(2(x-1))+10=x

We move all terms to the left:

(1/4)(2(x-1))+10-(x)=0


Domain of the equation: 4)(2(x-1))!=0

x∈R


We add all the numbers together, and all the variables

(+1/4)(2(x-1))-x+10=0

We add all the numbers together, and all the variables

-1x+(+1/4)(2(x-1))+10=0

We multiply all the terms by the denominator


-1x*4)(2(x-1))+(+10*4)(2(x-1))+1=0

We add all the numbers together, and all the variables

-1x*4)(2(x-1))+40(2(x-1))+1=0

Wy multiply elements

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$