(3x+9)+(3x+9)=(8x-22)

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Solution for (3x+9)+(3x+9)=(8x-22) equation: 



(3x+9)+(3x+9)=(8x-22)

We move all terms to the left:

(3x+9)+(3x+9)-((8x-22))=0

We get rid of parentheses

3x+3x-((8x-22))+9+9=0



We calculate terms in parentheses: -((8x-22)), so:

(8x-22)

We get rid of parentheses

8x-22

Back to the equation:

-(8x-22)



We add all the numbers together, and all the variables

6x-(8x-22)+18=0

We get rid of parentheses

6x-8x+22+18=0

We add all the numbers together, and all the variables

-2x+40=0

We move all terms containing x to the left, all other terms to the right

-2x=-40

x=-40/-2

x=+20

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