6y-(12+2y)=28

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Solution for 6y-(12+2y)=28 equation: 



6y-(12+2y)=28

We move all terms to the left:

6y-(12+2y)-(28)=0

We add all the numbers together, and all the variables

6y-(2y+12)-28=0

We get rid of parentheses

6y-2y-12-28=0

We add all the numbers together, and all the variables

4y-40=0

We move all terms containing y to the left, all other terms to the right

4y=40

y=40/4

y=10

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