-(7/4)x+(3/4)=-8

Solution for -(7/4)x+(3/4)=-8 equation:

-(7/4)x+(3/4)=-8

We move all terms to the left:

-(7/4)x+(3/4)-(-8)=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+7/4)x+(+3/4)-(-8)=0

We add all the numbers together, and all the variables

-(+7/4)x+8+(+3/4)=0

We multiply parentheses

-7x^2+8+(+3/4)=0

We get rid of parentheses

-7x^2+8+3/4=0

We multiply all the terms by the denominator


-7x^2*4+3+8*4=0

We add all the numbers together, and all the variables

-7x^2*4+35=0

Wy multiply elements

-28x^2+35=0

a = -28; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·(-28)·35
Δ = 3920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3920}=\sqrt{784*5}=\sqrt{784}*\sqrt{5}=28\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{5}}{2*-28}=\frac{0-28\sqrt{5}}{-56}
=-\frac{28\sqrt{5}}{-56}
=-\frac{\sqrt{5}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{5}}{2*-28}=\frac{0+28\sqrt{5}}{-56}
=\frac{28\sqrt{5}}{-56}
=\frac{\sqrt{5}}{-2}
$