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5(n+1)-2n=2(3+n)
We move all terms to the left:
5(n+1)-2n-(2(3+n))=0
We add all the numbers together, and all the variables
5(n+1)-2n-(2(n+3))=0
We add all the numbers together, and all the variables
-2n+5(n+1)-(2(n+3))=0
We multiply parentheses
-2n+5n-(2(n+3))+5=0
We calculate terms in parentheses: -(2(n+3)), so:We add all the numbers together, and all the variables
2(n+3)
We multiply parentheses
2n+6
Back to the equation:
-(2n+6)
3n-(2n+6)+5=0
We get rid of parentheses
3n-2n-6+5=0
We add all the numbers together, and all the variables
n-1=0
We move all terms containing n to the left, all other terms to the right
n=1
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