3(4x-5)=3-7(1-x)

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Solution for 3(4x-5)=3-7(1-x) equation: 



3(4x-5)=3-7(1-x)

We move all terms to the left:

3(4x-5)-(3-7(1-x))=0

We add all the numbers together, and all the variables

3(4x-5)-(3-7(-1x+1))=0

We multiply parentheses

12x-(3-7(-1x+1))-15=0



We calculate terms in parentheses: -(3-7(-1x+1)), so:

3-7(-1x+1)

determiningTheFunctionDomain
-7(-1x+1)+3

We multiply parentheses

7x-7+3

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We get rid of parentheses

12x-7x+4-15=0

We add all the numbers together, and all the variables

5x-11=0

We move all terms containing x to the left, all other terms to the right

5x=11

x=11/5

x=2+1/5

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