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3/5x+1=1/2x-2
We move all terms to the left:
3/5x+1-(1/2x-2)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x-2)!=0We get rid of parentheses
x∈R
3/5x-1/2x+2+1=0
We calculate fractions
6x/10x^2+(-5x)/10x^2+2+1=0
We add all the numbers together, and all the variables
6x/10x^2+(-5x)/10x^2+3=0
We multiply all the terms by the denominator
6x+(-5x)+3*10x^2=0
Wy multiply elements
30x^2+6x+(-5x)=0
We get rid of parentheses
30x^2+6x-5x=0
We add all the numbers together, and all the variables
30x^2+x=0
a = 30; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·30·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*30}=\frac{-2}{60} =-1/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*30}=\frac{0}{60} =0 $
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