5(c-8)+35=11-2c

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Solution for 5(c-8)+35=11-2c equation:



5(c-8)+35=11-2c
We move all terms to the left:
5(c-8)+35-(11-2c)=0
We add all the numbers together, and all the variables
5(c-8)-(-2c+11)+35=0
We multiply parentheses
5c-(-2c+11)-40+35=0
We get rid of parentheses
5c+2c-11-40+35=0
We add all the numbers together, and all the variables
7c-16=0
We move all terms containing c to the left, all other terms to the right
7c=16
c=16/7
c=2+2/7

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