(2x+1)/3=(4x-11)/5

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Solution for (2x+1)/3=(4x-11)/5 equation: 



(2x+1)/3=(4x-11)/5

We move all terms to the left:

(2x+1)/3-((4x-11)/5)=0

We calculate fractions


2x/()+(-((4x-11)*3)/()=0



We calculate terms in parentheses: +(-((4x-11)*3)/(), so:

-((4x-11)*3)/(

We multiply all the terms by the denominator


-((4x-11)*3)



We calculate terms in parentheses: -((4x-11)*3), so:

(4x-11)*3

We multiply parentheses

12x-33

Back to the equation:

-(12x-33)



We get rid of parentheses

-12x+33

Back to the equation:

+(-12x+33)



We get rid of parentheses

2x/()-12x+33=0

We multiply all the terms by the denominator


2x-12x*()+33*()=0

We add all the numbers together, and all the variables

2x-12x*()=0

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