6(z-9)=4(z-5)

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Solution for 6(z-9)=4(z-5) equation: 



6(z-9)=4(z-5)

We move all terms to the left:

6(z-9)-(4(z-5))=0

We multiply parentheses

6z-(4(z-5))-54=0



We calculate terms in parentheses: -(4(z-5)), so:

4(z-5)

We multiply parentheses

4z-20

Back to the equation:

-(4z-20)



We get rid of parentheses

6z-4z+20-54=0

We add all the numbers together, and all the variables

2z-34=0

We move all terms containing z to the left, all other terms to the right

2z=34

z=34/2

z=17

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