(6x+12)-78=(4x+6)

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Solution for (6x+12)-78=(4x+6) equation: 



(6x+12)-78=(4x+6)

We move all terms to the left:

(6x+12)-78-((4x+6))=0

We get rid of parentheses

6x-((4x+6))+12-78=0



We calculate terms in parentheses: -((4x+6)), so:

(4x+6)

We get rid of parentheses

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

6x-(4x+6)-66=0

We get rid of parentheses

6x-4x-6-66=0

We add all the numbers together, and all the variables

2x-72=0

We move all terms containing x to the left, all other terms to the right

2x=72

x=72/2

x=36

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