5(6-c)/2=-4(2c+7)/7

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Solution for 5(6-c)/2=-4(2c+7)/7 equation: 



5(6-c)/2=-4(2c+7)/7

We move all terms to the left:

5(6-c)/2-(-4(2c+7)/7)=0

We add all the numbers together, and all the variables

5(-1c+6)/2-(-4(2c+7)/7)=0

We calculate fractions


(-5c)/()+(-(-4(2c+7)*2)/()=0



We calculate terms in parentheses: +(-(-4(2c+7)*2)/(), so:

-(-4(2c+7)*2)/(

We multiply all the terms by the denominator


-(-4(2c+7)*2)



We calculate terms in parentheses: -(-4(2c+7)*2), so:

-4(2c+7)*2

We multiply parentheses

-16c-56

Back to the equation:

-(-16c-56)



We get rid of parentheses

16c+56

Back to the equation:

+(16c+56)



We get rid of parentheses

(-5c)/()+16c+56=0

We multiply all the terms by the denominator


(-5c)+16c*()+56*()=0

We add all the numbers together, and all the variables

(-5c)+16c*()=0

We get rid of parentheses

-5c+16c*()=0

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