3y-2+y+42=7y+40-5y

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Solution for 3y-2+y+42=7y+40-5y equation: 



3y-2+y+42=7y+40-5y

We move all terms to the left:

3y-2+y+42-(7y+40-5y)=0

We add all the numbers together, and all the variables

3y+y-(2y+40)-2+42=0

We add all the numbers together, and all the variables

4y-(2y+40)+40=0

We get rid of parentheses

4y-2y-40+40=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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