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7(x+3)=7(3+x)
We move all terms to the left:
7(x+3)-(7(3+x))=0
We add all the numbers together, and all the variables
7(x+3)-(7(x+3))=0
We multiply parentheses
7x-(7(x+3))+21=0
We calculate terms in parentheses: -(7(x+3)), so:We get rid of parentheses
7(x+3)
We multiply parentheses
7x+21
Back to the equation:
-(7x+21)
7x-7x-21+21=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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