19+4v=3(4v-2)+1

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Solution for 19+4v=3(4v-2)+1 equation: 



19+4v=3(4v-2)+1

We move all terms to the left:

19+4v-(3(4v-2)+1)=0



We calculate terms in parentheses: -(3(4v-2)+1), so:

3(4v-2)+1

We multiply parentheses

12v-6+1

We add all the numbers together, and all the variables

12v-5

Back to the equation:

-(12v-5)



We get rid of parentheses

4v-12v+5+19=0

We add all the numbers together, and all the variables

-8v+24=0

We move all terms containing v to the left, all other terms to the right

-8v=-24

v=-24/-8

v=+3

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