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5(4y+1)=3(4y-3)
We move all terms to the left:
5(4y+1)-(3(4y-3))=0
We multiply parentheses
20y-(3(4y-3))+5=0
We calculate terms in parentheses: -(3(4y-3)), so:We get rid of parentheses
3(4y-3)
We multiply parentheses
12y-9
Back to the equation:
-(12y-9)
20y-12y+9+5=0
We add all the numbers together, and all the variables
8y+14=0
We move all terms containing y to the left, all other terms to the right
8y=-14
y=-14/8
y=-1+3/4
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