(7x-2)+(3x+8)=9x+16

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Solution for (7x-2)+(3x+8)=9x+16 equation: 



(7x-2)+(3x+8)=9x+16

We move all terms to the left:

(7x-2)+(3x+8)-(9x+16)=0

We get rid of parentheses

7x+3x-9x-2+8-16=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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