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(6x+3)/2+2x=3x-5(x-1)
We move all terms to the left:
(6x+3)/2+2x-(3x-5(x-1))=0
We add all the numbers together, and all the variables
2x+(6x+3)/2-(3x-5(x-1))=0
We multiply all the terms by the denominator
2x*2+(6x+3)-((3x-5(x-1)))*2=0
Wy multiply elements
4x+(6x+3)-((3x-5(x-1)))*2=0
We get rid of parentheses
4x+6x-((3x-5(x-1)))*2+3=0
We add all the numbers together, and all the variables
10x-((3x-5(x-1)))*2+3=0
We move all terms containing x to the left, all other terms to the right
10x-((3x-5(x-1)))*2=-3
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