4(5z+35)=2(2z-2)

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Solution for 4(5z+35)=2(2z-2) equation: 



4(5z+35)=2(2z-2)

We move all terms to the left:

4(5z+35)-(2(2z-2))=0

We multiply parentheses

20z-(2(2z-2))+140=0



We calculate terms in parentheses: -(2(2z-2)), so:

2(2z-2)

We multiply parentheses

4z-4

Back to the equation:

-(4z-4)



We get rid of parentheses

20z-4z+4+140=0

We add all the numbers together, and all the variables

16z+144=0

We move all terms containing z to the left, all other terms to the right

16z=-144

z=-144/16

z=-9

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