7(b+2)=3(b+6)

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Solution for 7(b+2)=3(b+6) equation: 



7(b+2)=3(b+6)

We move all terms to the left:

7(b+2)-(3(b+6))=0

We multiply parentheses

7b-(3(b+6))+14=0



We calculate terms in parentheses: -(3(b+6)), so:

3(b+6)

We multiply parentheses

3b+18

Back to the equation:

-(3b+18)



We get rid of parentheses

7b-3b-18+14=0

We add all the numbers together, and all the variables

4b-4=0

We move all terms containing b to the left, all other terms to the right

4b=4

b=4/4

b=1

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