5(4+2x)=(-8x-12)=68

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Solution for 5(4+2x)=(-8x-12)=68 equation:



5(4+2x)=(-8x-12)=68
We move all terms to the left:
5(4+2x)-((-8x-12))=0
We add all the numbers together, and all the variables
5(2x+4)-((-8x-12))=0
We multiply parentheses
10x-((-8x-12))+20=0
We calculate terms in parentheses: -((-8x-12)), so:
(-8x-12)
We get rid of parentheses
-8x-12
Back to the equation:
-(-8x-12)
We get rid of parentheses
10x+8x+12+20=0
We add all the numbers together, and all the variables
18x+32=0
We move all terms containing x to the left, all other terms to the right
18x=-32
x=-32/18
x=-1+7/9

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