5(2w-1)+6(3w-4)=27

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Solution for 5(2w-1)+6(3w-4)=27 equation: 



5(2w-1)+6(3w-4)=27

We move all terms to the left:

5(2w-1)+6(3w-4)-(27)=0

We multiply parentheses

10w+18w-5-24-27=0

We add all the numbers together, and all the variables

28w-56=0

We move all terms containing w to the left, all other terms to the right

28w=56

w=56/28

w=2

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