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1/5x-1.2=1.8x
We move all terms to the left:
1/5x-1.2-(1.8x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-(+1.8x)-1.2=0
We get rid of parentheses
1/5x-1.8x-1.2=0
We multiply all the terms by the denominator
-(1.8x)*5x-(1.2)*5x+1=0
We add all the numbers together, and all the variables
-(+1.8x)*5x-(1.2)*5x+1=0
We multiply parentheses
-5x^2-6x+1=0
a = -5; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·(-5)·1
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{14}}{2*-5}=\frac{6-2\sqrt{14}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{14}}{2*-5}=\frac{6+2\sqrt{14}}{-10} $
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