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2/5x-5/5=2
We move all terms to the left:
2/5x-5/5-(2)=0
Domain of the equation: 5x!=0determiningTheFunctionDomain 2/5x-2-5/5=0
x!=0/5
x!=0
x∈R
We add all the numbers together, and all the variables
2/5x-3=0
We multiply all the terms by the denominator
-3*5x+2=0
Wy multiply elements
-15x+2=0
We move all terms containing x to the left, all other terms to the right
-15x=-2
x=-2/-15
x=2/15
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