10=3(2x-7)-(4x+1)-5(1-x)-x

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Solution for 10=3(2x-7)-(4x+1)-5(1-x)-x equation: 



10=3(2x-7)-(4x+1)-5(1-x)-x

We move all terms to the left:

10-(3(2x-7)-(4x+1)-5(1-x)-x)=0

We add all the numbers together, and all the variables

-(3(2x-7)-(4x+1)-5(-1x+1)-x)+10=0



We calculate terms in parentheses: -(3(2x-7)-(4x+1)-5(-1x+1)-x), so:

3(2x-7)-(4x+1)-5(-1x+1)-x

We add all the numbers together, and all the variables

-1x+3(2x-7)-(4x+1)-5(-1x+1)

We multiply parentheses

-1x+6x-(4x+1)+5x-21-5

We get rid of parentheses

-1x+6x-4x+5x-1-21-5

We add all the numbers together, and all the variables

6x-27

Back to the equation:

-(6x-27)



We get rid of parentheses

-6x+27+10=0

We add all the numbers together, and all the variables

-6x+37=0

We move all terms containing x to the left, all other terms to the right

-6x=-37

x=-37/-6

x=6+1/6

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