(3w-2)*w=40

Solution for (3w-2)*w=40 equation:

(3w-2)*w=40

We move all terms to the left:

(3w-2)*w-(40)=0

We multiply parentheses

3w^2-2w-40=0

a = 3; b = -2; c = -40;
Δ = b2-4ac
Δ = -22-4·3·(-40)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*3}=\frac{-20}{6}
=-3+1/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*3}=\frac{24}{6}
=4
$