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5(1-x)2-x(x-3)+2=6(x3-3x-7)-2x(x+5)
We move all terms to the left:
5(1-x)2-x(x-3)+2-(6(x3-3x-7)-2x(x+5))=0
We add all the numbers together, and all the variables
-(6(+x^3-3x-7)-2x(x+5))+5(-1x+1)2-x(x-3)+2=0
We multiply parentheses
-(6(+x^3-3x-7)-2x(x+5))-x^2-10x+3x+10+2=0
We calculate terms in parentheses: -(6(+x^3-3x-7)-2x(x+5)), so:
6(+x^3-3x-7)-2x(x+5)
We do not support expression: x^3
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