-4x-4(3-4x)=5(x-4)-20

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Solution for -4x-4(3-4x)=5(x-4)-20 equation: 



-4x-4(3-4x)=5(x-4)-20

We move all terms to the left:

-4x-4(3-4x)-(5(x-4)-20)=0

We add all the numbers together, and all the variables

-4x-4(-4x+3)-(5(x-4)-20)=0

We multiply parentheses

-4x+16x-(5(x-4)-20)-12=0



We calculate terms in parentheses: -(5(x-4)-20), so:

5(x-4)-20

We multiply parentheses

5x-20-20

We add all the numbers together, and all the variables

5x-40

Back to the equation:

-(5x-40)



We add all the numbers together, and all the variables

12x-(5x-40)-12=0

We get rid of parentheses

12x-5x+40-12=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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