4y-5=3+(3y+8)

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Solution for 4y-5=3+(3y+8) equation:



4y-5=3+(3y+8)
We move all terms to the left:
4y-5-(3+(3y+8))=0
We calculate terms in parentheses: -(3+(3y+8)), so:
3+(3y+8)
determiningTheFunctionDomain (3y+8)+3
We get rid of parentheses
3y+8+3
We add all the numbers together, and all the variables
3y+11
Back to the equation:
-(3y+11)
We get rid of parentheses
4y-3y-11-5=0
We add all the numbers together, and all the variables
y-16=0
We move all terms containing y to the left, all other terms to the right
y=16

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